BASH端末の下部に固定進行状況バーを作成する

@MatrixManAtYrServiceが提案したタスクを実行するためのテストスクリプトを作成しました。私はこのソリューションがU&L SEが適用されているすべてのシステムで動作しないことを知っていますが、これは私が必要とする仕様を満たしています。

#!/bin/bash

# go to last line and print the empty progress bar
tput sc #save the current cursor position
tput cup $((`tput lines`-1)) 3 # go to last line
echo -n "[" # the next 5 lines just print the required stuff to make the bar
for i in $(seq 1 $((`tput cols`-10))); do
    echo -n "-"
done
echo -n "]"
tput rc # bring the cursor back to the last saved position


# the actual loop which does the script's main job
for i in $(seq 0 10 100); do
    # print the filled progress bar
    tput sc  #save the current cursor position
    doned=${i}  #example value for completed amount
    total=100   #example value for total amount

    doned=`echo $doned $total | awk '{print ($1/$2)}'` # the next three lines calculate how many characters to print for the completed amount
    total=`tput cols | awk '{print $1-10}'`
    doned=`echo $doned $total | awk '{print int(($1*$2))}'`


    tput cup $((`tput lines`-1)) 4 #go to the last line
    for l in $(seq 1 $doned); do #this loop prints the required no. of "="s to fill the bar
        echo -n "="
    done
    tput rc #bring the cursor back to the last saved position

    # the next 7 lines are to find the row on which the cursor is currently on to check if it 
    # is at the last line 
    # (based on the accepted answer of this question: https://stackoverflow.com/questions/2575037/)
    exec < /dev/tty
    oldstty=$(stty -g)
    stty raw -echo min 0
    tput u7 > /dev/tty
    IFS=';' read -r -d R -a pos
    stty $oldstty
    row=$((${pos[0]:2} - 1))


    # check if the cursor is on the line before the last line, if yes, clear the terminal, 
    # and make the empty bar again and fill it with the required amount of "="s
    if [ $row -gt $((`tput lines`-2)) ]; then
        clear
        tput sc
        tput cup $((`tput lines`-1)) 3
        echo -n "["

        for j in $(seq 1 $((`tput cols`-10))); do
            echo -n "-"
        done
        echo -n "]"
        tput cup $((`tput lines`-1)) 4
        for k in $(seq 1 $doned); do
            echo -n "="
        done
        tput rc
    fi

    # this is just to show that the cursor is behaving correctly
    read -p "Do you want to continue? (y/n)" yn;  

done

 # the next few lines remove the progress bar after the program is over   
tput sc # save the current cursor position
tput cup $((`tput lines`-1)) 3 # go to the line with the progress bar
tput el # clear the current line
tput rc # go back to the saved cursor position

端末を消去するよりも、最後の行のオーバーフローを処理するより良い方法が必要です。これは@MatrixManAtYrServiceが提案した概念証明に近い。制限事項の改善やコメントを歓迎します。