Bashスクリプト：ユーザー入力（読み取り）が正しく機能しません。

ファイルを削除するか、名前、内容に基づいてプログラムを閉じるBASHスクリプトを作成しています。特に、内容に応じてファイルを削除するのに問題があります（ケース2）。コンテンツに一致するすべてのファイルでファイルを入力できます。ただし、ユーザーがファイルを削除するかどうか（読み取りを使用）を入力する必要がある場合、私のコードは破損します。この変数は、ユーザー入力を要求せずに、削除するファイルの場所を自動的に入力します。

#!/bin/bash

#set -x
#Programmer: Redacted
#Z: ID: Redacted
#Assignment:  cleaner.sh

directory=`pwd` #sets the directory variable to pwd
string="string"
file="file"
fileFound=matched.txt
possibleFiles=''
result=''
function askDelete #asks for verification
{
    #echo "$fileName was found, still want to delete it? (y/n)"
    read -p "$fileName was found, still want to delete it? (y/n)" continue
    echo "Continue is equal to: $continue"
}


echo    "Welcome to my CLEANER script!"
echo    "Enter 1: delete by filename."
echo    "Enter 2: delete by a string within the file."
echo    "Enter 3 or quit: exit this program."
read command
    case $command in
    "file")
        command=1 ;;
    "string")
        command=2 ;;
    esac

case $command in
    1)
            #Prompts user for which file they want to delete
        echo "What file would you like to delete? "
        read fileName
        #find $PWD -type f -name "$fileName"
        #result= -x $fileName
        if [ -a "$fileName" ]
            then
                askDelete
                if [ $continue == 'y' ] || [ $continue == 'Y' ]
                    then
                        rm $fileName
                        echo "File has been removed"
                    else
                        echo "File has not been removed"
                fi

            else
                echo "No files were found"
        fi

    ;;

    #case where user entered 2
    #user wants to enter a string within the files to delete
    2)
        touch 'matched.txt' #creates the file that will be used
        echo "Enter the string that you wish to have the files containing it to be destroyed"
        read pattern    #user enters what they want to search for
        find $PWD -type f 1>possibleFiles.txt
        #echo $PWD
        #grep -q "$pattern" 'foundFile.txt' 1> matched.txt
        echo 'This is where it breaks'
        cat possibleFiles.txt | while read fileName
        do
            #\echo $fileName
            grep -q "$pattern" "$fileName" 1> matched.txt
            if [ $? == 0 ]
            then
                askDelete
                if [ $continue == 'y' ] || [ $continue == 'Y' ]
                    then
                        rm $fileName
                    else
                        echo  "No found files have been removed"
                fi
            else
                echo "No matches for the pattern were found"
            fi
        done
#
#       if [ $? == 0 ]
#           then
#               askDelete
#               if [ $continue == "Y" ] || [ $continue == "y" ]
#                   then
#                       #cat matched.txt 
#                       for file in 'matched.txt'
#                       do
    #                       echo 'bleh'
#                       done
    #               else
#                       echo  "No found files have been removed"
#               fi
#           else
#               echo "No matches for the pattern were found"
#       fi
#       fi
        ;;

    #case where user entered 3
    #user wants to exit
    3)
        echo "Goodbye friend"
        exit
    ;;

    *)
        echo Digit 1, 2 or 3 must be entered
esac

私は問題がプログラムの上部近くのAskDelete関数の内部のどこかにあると思います。具体的には、次の行は次のとおりです。 read -p "$fileName が見つかりましたが、まだ削除しますか? (y/n)" continue

助けてくれてありがとう。