4つのJSONファイルをマージしようとしています(今後さらに2つを追加する可能性があります)。改行で区切られたJSONファイル間の唯一の共通要素は「vulnid」です。
File 1:
{"vulnid":"cve1", "product":"product1"}
{"vulnid":"cve2", "product":"product2"}
{"vulnid":"cve3", "product":"product3"}
{"vulnid":"cve4", "product":""}
{"vulnid":"cve5", "product":""}
{"vulnid":"cve6", "product":""}
File 2:
{"vulnid":"cve1", "version":"version1"}
{"vulnid":"cve2", "version":"version2"}
{"vulnid":"cve3", "version":"version3"}
{"vulnid":"cve4", "version":"version4"}
File 3:
{"vulnid":"cve1", "patch":"patch1"}
{"vulnid":"cve2", "patch":"patch2"}
{"vulnid":"cve3", "patch":"patch3"}
{"vulnid":"cve4", "patch":""}
File 4:
{"vulnid":"cve1", "speed":"speed1"}
{"vulnid":"cve2", "power":"power2"}
{"vulnid":"cve3", "amps":"amps3"}
{"vulnid":"cve4", "product":"product4"}
{"vulnid":"cve4", "patch":"patch4"}
Required output:
{"vulnid":"cve1", "product":"product1", "version":"version1", "patch":"patch1", "speed":"speed1"}
{"vulnid":"cve2", "product":"product2", "version":"version2", "patch":"patch2", "power":"power2"}
{"vulnid":"cve3", "product":"product3", "version":"version3", "patch":"patch3", "amps":"amps3"}
{"vulnid":"cve4", "product":"product4", "version":"version4", "patch":"patch4"}
{"vulnid":"cve5", "product":""}
{"vulnid":"cve6", "product":""}
私が今まで試したこと:
jq -s '.[0] * .[1] * .[3] * .[4]' json1 json2 json3 json4
jq -s '.[0] + .[1] + .[3] + .[4]' json1 json2 json3 json4
...そして、jqのさまざまな組み合わせはすべて間違った結果を提供し、ツールについて私が理解していないことを示しています。
「vulnid」フィールドとjqフィールドを使用してこのマージを実行できますか?
ベストアンサー1
最短jq
解決策:
jq -sc 'group_by(.vulnid)[] | add' file*.json
出力:
{"vulnid":"cve1","product":"product1","version":"version1","patch":"patch1","speed":"speed1"}
{"vulnid":"cve2","product":"product2","version":"version2","patch":"patch2","power":"power2"}
{"vulnid":"cve3","product":"product3","version":"version3","patch":"patch3","amps":"amps3"}
{"vulnid":"cve4","product":"product4","version":"version4","patch":"patch4"}
{"vulnid":"cve5","product":""}
{"vulnid":"cve6","product":""}