parent_directory/次のサブディレクトリとを含むディレクトリがchild1/あるchild2/としますchild3/。
zipすべての*.txtファイルをそのディレクトリに書き込むためのスクリプトを作成childx/するにはどうすればよいですか？childx.zipchildx.zipchildx/
ベストアンサー1
サンプル
$ mkdir -p parent_directory/child{1..3}
$ touch parent_directory/child{1..3}/file1.txt
$ touch parent_directory/child{1..3}/file2.txt
$ tree parent_directory/
parent_directory/
├── child1
│ ├── file1.txt
│ └── file2.txt
├── child2
│ ├── file1.txt
│ └── file2.txt
└── child3
├── file1.txt
└── file2.txt
3 directories, 6 files
解決策
次に、zipファイルをスクリプトとして作成します。
$ cd parent_directory/; for i in *; do find ${i} -name "*.txt" -print | zip ${i}.zip -@; mv ${i}.zip ${i}; done; cd -
adding: child1/file2.txt (stored 0%)
adding: child1/file1.txt (stored 0%)
adding: child2/file2.txt (stored 0%)
adding: child2/file1.txt (stored 0%)
adding: child3/file2.txt (stored 0%)
adding: child3/file1.txt (stored 0%)
結果
結果：
$ tree parent_directory/
parent_directory/
├── child1
│ ├── child1.zip
│ ├── file1.txt
│ └── file2.txt
├── child2
│ ├── child2.zip
│ ├── file1.txt
│ └── file2.txt
└── child3
├── child3.zip
├── file1.txt
└── file2.txt
3 directories, 9 files
$ unzip -l parent_directory/child1/child1.zip
Archive: parent_directory/child1/child1.zip
Length Date Time Name
--------- ---------- ----- ----
0 07-05-2018 10:08 child1/file2.txt
0 07-05-2018 10:08 child1/file1.txt
--------- -------
0 2 files
$ unzip -l parent_directory/child2/child2.zip
Archive: parent_directory/child2/child2.zip
Length Date Time Name
--------- ---------- ----- ----
0 07-05-2018 10:08 child2/file2.txt
0 07-05-2018 10:08 child2/file1.txt
--------- -------
0 2 files
$ unzip -l parent_directory/child3/child3.zip
Archive: parent_directory/child3/child3.zip
Length Date Time Name
--------- ---------- ----- ----
0 07-05-2018 10:08 child3/file2.txt
0 07-05-2018 10:08 child3/file1.txt
--------- -------
0 2 files