☰

複数の変数に「読み取り」を使用する

tag-icon • tag-icon bash docker read
複数の変数に「読み取り」を使用する

だから私は基本的にDockerアプリケーションをすばやく実行するためのスクリプトを書いています。

私の機能の1つについて質問があります。

function prompt_user() {
    echo "Enter details for docker build! If it's a new build, you can leave Host Directory and Remote Directory blank."
    echo "If you've already assigned variables and are running the host you can leave the already filled vars blank if you entered them before"
    echo " "
    echo "Enter details:"
    read -p "Image Name: " IMAGE_NAME
    read -p "IP Address: " IP_ADDRESS
    read -p "Port 1: " PORT_ONE
    read -p "Port 2: " PORT_TWO
    read -p "Container Name: " CONTAINER_NAME
    read -p "Node Name: " NODE_NAME
    read -p "Host Directory (Can leave this blank if you're building a new image): " HOST_DIRECTORY
    read -p "Remote Directory (Can leave this blank if you're building a new image): " REMOTE_DIRECTORY
}

冗長読み取りを減らし、すべての入力を変数に割り当てる簡単な方法はありますか？

ここ確認したい場合は、スクリプト全体があります。

ベストアンサー1

これが既存の関数よりどれほどきれいかはわかりませんが、forループと組み合わせた連想配列（bash v4.0以降が必要）を使用すると、時間読み取りを使用できます。

function prompt_user() {
    declare -A prompt_questions
    vars=(IMAGE_NAME IP_ADDRESS PORT_ONE PORT_TWO CONTAINER_NAME NODE_NAME HOST_DIRECTORY REMOTE_DIRECTORY)
    prompt_questions=(
        [IMAGE_NAME]='Image Name'
        [IP_ADDRESS]='IP Address'
        [PORT_ONE]='Port 1'
        [PORT_TWO]='Port 2'
        [CONTAINER_NAME]='Container Name'
        [NODE_NAME]='Node Name'
        [HOST_DIRECTORY]="Host Directory (Can leave this blank if you're building a new image)"
        [REMOTE_DIRECTORY]="Remote Directory (Can leave this blank if you're building a new image)"
    )
    cat <<EOF
Enter details for docker build! If it's a new build, you can leave Host Directory and Remote Directory blank.
If you've already assigned variables and are running the host you can leave the already filled vars blank if you entered them before

Enter details:
EOF
    for var in "${vars[@]}"; do
        read -rp "${prompt_questions[$var]}: " "$var"
    done
}

おすすめ記事