Bash - 評価なしで動的メニュー選択を作成する方法

私はDocker環境のためのスクリプトを書いていますが、私が抜けた穴に閉じ込められているようです。

#!/bin/bash

set -euo pipefail

# Variables
gituser="modem7"
gitrepo="docker-devenv"
gitfolder="Environments"
buildername="DockerDevBuilder"

# Colours
RED="\e[31m"
GREEN="\e[32m"
END="\e[0m"

echo "========================================="
printf "        Checking Dependencies\n"
echo "========================================="
printf "Checking if dependencies are installed...\n"
pkg_list=(docker jq)
tc() { set ${*,,} ; echo ${*^} ; }
for pkg in "${pkg_list[@]}"
do
  titlecase=$(tc $pkg)
  isinstalled=$(dpkg-query -l $pkg > /dev/null 2>&1)
    if [ $? -eq 0 ];
     then
       printf "~ $titlecase is...${GREEN}installed${END}\n"
     else
       printf "~ $titlecase is...${RED}not installed${END}\n"
       printf "Exiting Script. Install $pkg.\n"
       echo "========================================="
       exit
    fi
done
echo "========================================="

cat << "EOF" 
      ____             _             
     |  _ \  ___   ___| | _____ _ __ 
     | | | |/ _ \ / __| |/ / _ | '__|
     | |_| | (_) | (__|   |  __| |   
     |____/ \___/ \___|_|\_\___|_|   
=========================================
EOF

PS3="Choose Option: "
dev_list=($(curl -fks https://api.github.com/repos/$gituser/$gitrepo/contents/$gitfolder | jq '. [] | .name' | tr -d '[]," '))
dev_list_array="${dev_list[*]}"
dev_list_array_pipe="${dev_list_array// /|}"
dev_list+=( "Prune" "Quit" )
echo -e "\nSelect an option:\n"
select dev_name in "${dev_list[@]}"; do
echo -e "\nYou've selected ${GREEN}${dev_name}${END}\n"
lowerdev=$(echo $dev_name | tr '[:upper:]' '[:lower:]')
    eval "case \"$dev_name\" in
      "$dev_list_array_pipe")
          echo "Creating buildx builder..."
          if docker buildx create --use --name "$buildername" > /dev/null 2>&1; then
              echo ""
              echo "Builder $buildername created"
            else
              echo "Builder already created, using $buildername"
              docker buildx use "DockerDevBuilder"
              echo ""
          fi
          echo "Creating $dev_name Environment..."
          docker buildx build --rm=true --build-arg BUILDKIT_INLINE_CACHE=1 --load -t $lowerdev:dev https://github.com/$gituser/$gitrepo.git#:$gitfolder/$dev_name \
          && clear \
          && echo "=========================================" \
          && echo "Activating $dev_name Dev Environment..." \
          && echo "Press CTRL + D or type exit to leave the container" \
          && docker run --rm -it --name "$dev_name"Dev"$RANDOM" --hostname "$dev_name"Dev"$RANDOM" "$lowerdev:dev"
          break
          ;;
      "Prune")
          echo "Clearing Docker cache..."
          docker system prune -af
          echo ""
          echo "Removing Docker buildx builder..."
          if docker buildx rm "$buildername" > /dev/null 2>&1; then
              echo ""
              echo "Builder $buildername removed"
            else
              echo "Builder already removed, no action performed"
              echo ""
          fi          
          exec bash $0
          ;;
      "Quit")
          echo "Exiting script"
          exit
          ;;
       *)
          echo "invalid option $REPLY"
          ;;
    esac"
done

exit 0

私は現在 " eval "case \"$dev_name\" in"を使用していますが、私が読んだところによると、これは問題があるようです。

うまくいきますが、そのような結果を得るより良い方法があるかどうかはわかりません。

これらのオプションはフォルダ名に基づいて生成されます。買戻契約しかし、evalの使用を削除する方法がわかりません。私が無駄な心配をしているのか？