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How can I tell jackson to ignore a property for which I don't have control over the source code? Ask Question

tag-icon • tag-icon java json jackson
How can I tell jackson to ignore a property for which I don't have control over the source code? Ask Question

Long story short, one of my entities has a GeometryCollection that throws an exception when you call "getBoundary" (the why of this is another book, for now let's say this is the way it works).

Is there a way I can tell Jackson not to include that specific getter? I know I can use @JacksonIgnore when I do own/control the code. But this is not case, jackson ends reaching this point through continuous serialization of the parent objects. I saw a filtering option in jackson documentation. Is that a plausible solution?

Thanks!

ベストアンサー1

You can use Jackson Mixins. For example:

class YourClass {
  public int ignoreThis() { return 0; }    
}

With this Mixin

abstract class MixIn {
  @JsonIgnore abstract int ignoreThis(); // we don't need it!  
}

With this:

objectMapper.getSerializationConfig().addMixInAnnotations(YourClass.class, MixIn.class);

Edit:

Thanks to the comments, with Jackson 2.5+, the API has changed and should be called with objectMapper.addMixIn(Class<?> target, Class<?> mixinSource)

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