ディレクトリの深さに応じたシンボリックリンク

これが私が問題を解決した方法です。これは最善のアプローチではないかもしれませんが、迅速な解決策が必要です。たぶん他の人が必要かもしれません

#!/usr/bin/bash

function main()
{
[ $# -ne 1 ] && { echo "Usage: $0 file"; exit 1; }
depth1=/a.zip
depth2=/b.zip
depth2_special=/special.zip
depth3=/c.zip
depth4=/d.zip

cat $1 | while read line; do
#Count the number of occurences of / in each line 
x=`echo $line |awk -F/ '{c += NF - 1} END {print c}'`
if [ $x -eq 13 ] ;then echo "The path has 13 / " 
    ln -sf $depth4 $line 
else
    if [ $x -eq 12 ] ;then echo "The path has 12 /"
        ln -sf $depth3 $line 
    else
        if [ $x -eq 11 ] ; then echo "The path has 11 /"
            #If there is no _ in the file path treat it as a special case
            underscore=`echo $line |awk -F_ '{c += NF - 1} END {print c}'`
                if [ $underscore -eq 1 ] ; then
                    ln -sf $depth2 $line
                else
                    ln -sf $depth2_special $line 
                fi; 
        else
            if [ $x -eq 10 ] ;then echo "The path has 10 /" 
                ln -sf $depth1 $line 
            else
                echo "Error - the path is not correct" 
            fi;
        fi;
    fi; 
fi;
done

}

main "$@"