シェルスクリプトは約1分後に自動的に停止します。

私は本当に醜いシェルスクリプトを書いていましたが、ある瞬間はうまくいきました。これで1〜2分間動作してから終了します。醜いことはわかりますが動作するので絶対に変えません。誰でも何が間違っているのか教えてもらえますか？どんな助けにも感謝します:)

#!/bin/bash
echo "Starting..."
timestamphour=`date +%F_%H`
mkdir /Some/Directory1
mkdir /Some/Directory2
mkdir /Some/Directory3
mkdir /Some/Directory4
mkdir /Some/Directory5
mkdir /Some/Directory6
mkdir /Some/Directory7
mkdir /Some/Directory8
mkdir /Some/Directory9

#This could be done in one step
mkdir /Some/Directory1/$timestamphour
mkdir /Some/Directory2/$timestamphour
mkdir /Some/Directory3/$timestamphour
mkdir /Some/Directory4/$timestamphour
mkdir /Some/Directory5/$timestamphour
mkdir /Some/Directory6/$timestamphour
mkdir /Some/Directory7/$timestamphour
mkdir /Some/Directory8/$timestamphour
mkdir /Some/Directory9/$timestamphour

for i in {1..3600}
do
#timestampmin=`date +%F_%H-%M`
timestampsec=`date +%F_%H-%M-%S`
sudo curl -o /Some/Directory1/$timestamphour/$timestampsec.jpg http://some.address.at.some:port1/jpg/image.jpg &
sudo curl -o /Some/Directory2/$timestamphour/$timestampsec.jpg http://some.address.at.some:port2/jpg/image.jpg &
sudo curl -o /Some/Directory3/$timestamphour/$timestampsec.jpg http://some.address.at.some:port3/jpg/image.jpg &
sudo curl -o /Some/Directory4/$timestamphour/$timestampsec.jpg http://some.address.at.some:port4/jpg/image.jpg &
sudo curl -o /Some/Directory5/$timestamphour/$timestampsec.jpg http://some.address.at.some:port5/jpg/image.jpg &
sudo curl -o /Some/Directory6/$timestamphour/$timestampsec.jpg http://some.address.at.some:port6/jpg/image.jpg &
sudo curl -o /Some/Directory7/$timestamphour/$timestampsec.jpg http://some.address.at.some:port7/jpg/image.jpg &
sudo curl -o /Some/Directory8/$timestamphour/$timestampsec.jpg http://some.address.at.some:port8/jpg/image.jpg &
sudo curl -o /Some/Directory9/$timestamphour/$timestampsec.jpg http://some.address.at.some:port9/jpg/image.jpg &
sleep 1
done