I have a bash script that launches a child process that crashes (actually, hangs) from time to time and with no apparent reason (closed source, so there isn't much I can do about it). As a result, I would like to be able to launch this process for a given amount of time, and kill it if it did not return successfully after a given amount of time.
Is there a simple and robust way to achieve that using bash?
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(As seen in: BASH FAQ entry #68: "How do I run a command, and have it abort (timeout) after N seconds?")
You can use timeout*:
timeout 10 ping www.goooooogle.com
Otherwise, do what timeout does internally:
( cmdpid=$BASHPID; (sleep 10; kill $cmdpid) & exec ping www.goooooogle.com )
In case you want to do a timeout for longer bash code, use the second option as such:
( cmdpid=$BASHPID;
(sleep 10; kill $cmdpid) \
& while ! ping -w 1 www.goooooogle.com
do
echo crap;
done )
* It's included in GNU Coreutils 8+, so most current Linux systems have it installed already, otherwise you can install it, e.g. sudo apt-get install timeout or sudo apt-get install coreutils